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Постройте график функции:

\nа) y = x² − 16/|x − 4|\n
\nб) y = x² − 25/5 + |x|\n\n\n

"}}]]}],["$","div",null,{"className":"notice","children":["Разбор этого задания готовится. Пока можно ",["$","a",null,{"href":"/reshit","children":"решить его по фото"}]," — ИИ объяснит по шагам."]}]]}]],["$","p",null,{"children":[["$","a",null,{"href":"/gdz/algebra/8-klass/makarychev/nomer-263","children":["← ","Номер 263"]}]," · ",["$","a",null,{"href":"/gdz/algebra/8-klass/makarychev/nomer-265","children":["Номер 265"," →"]}]," · ",["$","a",null,{"href":"/gdz/algebra/8-klass/makarychev","children":"Все номера"}]]}],["$","script",null,{"type":"application/ld+json","dangerouslySetInnerHTML":{"__html":"[{\"@context\":\"https://schema.org\",\"@type\":\"Question\",\"name\":\"Алгебра 8 класс Макарычев, номер 264\",\"text\":\"Постройте график функции: а) y = x² − 16/|x − 4| б) y = x² − 25/5 + |x|\",\"answerCount\":1,\"acceptedAnswer\":{\"@type\":\"Answer\",\"text\":\"Ответ: а) Две прямые: y = x + 4 при x > 4 и y = −x − 4 при x < 4; точка (4; 8) и (4; −8) исключены.\\n\\nб) Две прямые, образующие угол: y = −x − 5 при x < 0 и y = x − 5 при x ≥ 0; вершина угла в точке (0; −5).\"}},{\"@context\":\"https://schema.org\",\"@type\":\"BreadcrumbList\",\"itemListElement\":[{\"@type\":\"ListItem\",\"position\":1,\"name\":\"Главная\",\"item\":\"https://reshay.ai/\"},{\"@type\":\"ListItem\",\"position\":2,\"name\":\"ГДЗ\",\"item\":\"https://reshay.ai/gdz\"},{\"@type\":\"ListItem\",\"position\":3,\"name\":\"Алгебра 8 класс Макарычев\",\"item\":\"https://reshay.ai/gdz/algebra/8-klass/makarychev\"},{\"@type\":\"ListItem\",\"position\":4,\"name\":\"Номер 264\"}]}]"}}]]

Номер 264 — ГДЗ алгебра 8 класс Макарычев